Step by Step Solution
Step 1 :
Equation at the end of step 1 :
(((z3) - 3z2) + 3z) - 1
Step 2 :
Checking for a perfect cube :
2.1 z3-3z2+3z-1 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: z3-3z2+3z-1
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 3z-1
Group 2: -3z2+z3
Pull out from each group separately :
Group 1: (3z-1) • (1)
Group 2: (z-3) • (z2)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
2.3 Find roots (zeroes) of : F(z) = z3-3z2+3z-1
Polynomial Roots Calculator is a set of methods aimed at finding values of z for which F(z)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers z which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -8.00 | ||||||
| 1 | 1 | 1.00 | 0.00 | z-1 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
z3-3z2+3z-1
can be divided with z-1
Polynomial Long Division :
2.4 Polynomial Long Division
Dividing : z3-3z2+3z-1
("Dividend")
By : z-1 ("Divisor")
| dividend | z3 | - | 3z2 | + | 3z | - | 1 | ||
| - divisor | * z2 | z3 | - | z2 | |||||
| remainder | - | 2z2 | + | 3z | - | 1 | |||
| - divisor | * -2z1 | - | 2z2 | + | 2z | ||||
| remainder | z | - | 1 | ||||||
| - divisor | * z0 | z | - | 1 | |||||
| remainder | 0 |
Quotient : z2-2z+1 Remainder: 0
Trying to factor by splitting the middle term
2.5 Factoring z2-2z+1
The first term is, z2 its coefficient is 1 .
The middle term is, -2z its coefficient is -2 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 1 • 1 = 1
Step-2 : Find two factors of 1 whose sum equals the coefficient of the middle term, which is -2 .
| -1 | + | -1 | = | -2 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and -1
z2 - 1z - 1z - 1
Step-4 : Add up the first 2 terms, pulling out like factors :
z • (z-1)
Add up the last 2 terms, pulling out common factors :
1 • (z-1)
Step-5 : Add up the four terms of step 4 :
(z-1) • (z-1)
Which is the desired factorization
Multiplying Exponential Expressions :
2.6 Multiply (z-1) by (z-1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (z-1) and the exponents are :
1 , as (z-1) is the same number as (z-1)1
and 1 , as (z-1) is the same number as (z-1)1
The product is therefore, (z-1)(1+1) = (z-1)2
Multiplying Exponential Expressions :
2.7 Multiply (z-1)2 by (z-1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (z-1) and the exponents are :
2
and 1 , as (z-1) is the same number as (z-1)1
The product is therefore, (z-1)(2+1) = (z-1)3
Final result :
(z - 1)3
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