Solution - Quadratic equations
Step by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((23•54x2) + 15x) - 16 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 5000x2+15x-16
The first term is, 5000x2 its coefficient is 5000 .
The middle term is, +15x its coefficient is 15 .
The last term, "the constant", is -16
Step-1 : Multiply the coefficient of the first term by the constant 5000 • -16 = -80000
Step-2 : Find two factors of -80000 whose sum equals the coefficient of the middle term, which is 15 .
| -80000 | + | 1 | = | -79999 | ||
| -40000 | + | 2 | = | -39998 | ||
| -20000 | + | 4 | = | -19996 | ||
| -16000 | + | 5 | = | -15995 | ||
| -10000 | + | 8 | = | -9992 | ||
| -8000 | + | 10 | = | -7990 |
For tidiness, printing of 34 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
5000x2 + 15x - 16 = 0
Step 3 :
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = 5000x2+15x-16
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 5000 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -0.0015
Plugging into the parabola formula -0.0015 for x we can calculate the y -coordinate :
y = 5000.0 * -0.00 * -0.00 + 15.0 * -0.00 - 16.0
or y = -16.011
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 5000x2+15x-16
Axis of Symmetry (dashed) {x}={-0.00}
Vertex at {x,y} = {-0.00,-16.01}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-0.06, 0.00}
Root 2 at {x,y} = { 0.06, 0.00}
Solve Quadratic Equation by Completing The Square
3.2 Solving 5000x2+15x-16 = 0 by Completing The Square .
Divide both sides of the equation by 5000 to have 1 as the coefficient of the first term :
x2+(3/1000)x-(2/625) = 0
Add 2/625 to both side of the equation :
x2+(3/1000)x = 2/625
Now the clever bit: Take the coefficient of x , which is 3/1000 , divide by two, giving 3/2000 , and finally square it giving 3/2000
Add 3/2000 to both sides of the equation :
On the right hand side we have :
2/625 + 3/2000 The common denominator of the two fractions is 10000 Adding (32/10000)+(15/10000) gives 47/10000
So adding to both sides we finally get :
x2+(3/1000)x+(3/2000) = 47/10000
Adding 3/2000 has completed the left hand side into a perfect square :
x2+(3/1000)x+(3/2000) =
(x+(3/2000)) • (x+(3/2000)) =
(x+(3/2000))2
Things which are equal to the same thing are also equal to one another. Since
x2+(3/1000)x+(3/2000) = 47/10000 and
x2+(3/1000)x+(3/2000) = (x+(3/2000))2
then, according to the law of transitivity,
(x+(3/2000))2 = 47/10000
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x+(3/2000))2 is
(x+(3/2000))2/2 =
(x+(3/2000))1 =
x+(3/2000)
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x+(3/2000) = √ 47/10000
Subtract 3/2000 from both sides to obtain:
x = -3/2000 + √ 47/10000
Since a square root has two values, one positive and the other negative
x2 + (3/1000)x - (2/625) = 0
has two solutions:
x = -3/2000 + √ 47/10000
or
x = -3/2000 - √ 47/10000
Note that √ 47/10000 can be written as
√ 47 / √ 10000 which is √ 47 / 100
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving 5000x2+15x-16 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 5000
B = 15
C = -16
Accordingly, B2 - 4AC =
225 - (-320000) =
320225
Applying the quadratic formula :
-15 ± √ 320225
x = ————————
10000
Can √ 320225 be simplified ?
Yes! The prime factorization of 320225 is
5•5•12809
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 320225 = √ 5•5•12809 =
± 5 • √ 12809
√ 12809 , rounded to 4 decimal digits, is 113.1769
So now we are looking at:
x = ( -15 ± 5 • 113.177 ) / 10000
Two real solutions:
x =(-15+√320225)/10000=(-3+√ 12809 )/2000= 0.055
or:
x =(-15-√320225)/10000=(-3-√ 12809 )/2000= -0.058
Two solutions were found :
- x =(-15-√320225)/10000=(-3-√ 12809 )/2000= -0.058
- x =(-15+√320225)/10000=(-3+√ 12809 )/2000= 0.055
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