Solution - Quadratic equations
Other Ways to Solve
Quadratic equationsStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "0.1" was replaced by "(1/10)". 2 more similar replacement(s)
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
4*x^2-((14/100)*((1/10)-x))=0
Step by step solution :
Step 1 :
1
Simplify ——
10
Equation at the end of step 1 :
14 1
(4•(x2))-(———•(——-x)) = 0
100 10
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 10 as the denominator :
x x • 10
x = — = ——————
1 10
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
1 - (x • 10) 1 - 10x
———————————— = ———————
10 10
Equation at the end of step 2 :
14 (1 - 10x)
(4 • (x2)) - (——— • —————————) = 0
100 10
Step 3 :
7
Simplify ——
50
Equation at the end of step 3 :
7 (1 - 10x)
(4 • (x2)) - (—— • —————————) = 0
50 10
Step 4 :
Equation at the end of step 4 :
7 • (1 - 10x) (4 • (x2)) - ————————————— = 0 500Step 5 :
Equation at the end of step 5 :
7 • (1 - 10x)
22x2 - ————————————— = 0
500
Step 6 :
Rewriting the whole as an Equivalent Fraction :
6.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 500 as the denominator :
22x2 22x2 • 500
22x2 = ———— = ——————————
1 500
Adding fractions that have a common denominator :
6.2 Adding up the two equivalent fractions
22x2 • 500 - (7 • (1-10x)) 2000x2 + 70x - 7
—————————————————————————— = ————————————————
500 500
Trying to factor by splitting the middle term
6.3 Factoring 2000x2 + 70x - 7
The first term is, 2000x2 its coefficient is 2000 .
The middle term is, +70x its coefficient is 70 .
The last term, "the constant", is -7
Step-1 : Multiply the coefficient of the first term by the constant 2000 • -7 = -14000
Step-2 : Find two factors of -14000 whose sum equals the coefficient of the middle term, which is 70 .
| -14000 | + | 1 | = | -13999 | ||
| -7000 | + | 2 | = | -6998 | ||
| -3500 | + | 4 | = | -3496 | ||
| -2800 | + | 5 | = | -2795 | ||
| -2000 | + | 7 | = | -1993 | ||
| -1750 | + | 8 | = | -1742 |
For tidiness, printing of 34 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 6 :
2000x2 + 70x - 7
———————————————— = 0
500
Step 7 :
When a fraction equals zero :
7.1 When a fraction equals zero ...Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
2000x2+70x-7
———————————— • 500 = 0 • 500
500
Now, on the left hand side, the 500 cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
2000x2+70x-7 = 0
Parabola, Finding the Vertex :
7.2 Find the Vertex of y = 2000x2+70x-7
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 2000 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is -0.0175
Plugging into the parabola formula -0.0175 for x we can calculate the y -coordinate :
y = 2000.0 * -0.02 * -0.02 + 70.0 * -0.02 - 7.0
or y = -7.612
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 2000x2+70x-7
Axis of Symmetry (dashed) {x}={-0.02}
Vertex at {x,y} = {-0.02,-7.61}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-0.08, 0.00}
Root 2 at {x,y} = { 0.04, 0.00}
Solve Quadratic Equation by Completing The Square
7.3 Solving 2000x2+70x-7 = 0 by Completing The Square .
Divide both sides of the equation by 2000 to have 1 as the coefficient of the first term :
x2+(7/200)x-(7/2000) = 0
Add 7/2000 to both side of the equation :
x2+(7/200)x = 7/2000
Now the clever bit: Take the coefficient of x , which is 7/200 , divide by two, giving 7/400 , and finally square it giving 49/160000
Add 49/160000 to both sides of the equation :
On the right hand side we have :
7/2000 + 49/160000 The common denominator of the two fractions is 160000 Adding (560/160000)+(49/160000) gives 609/160000
So adding to both sides we finally get :
x2+(7/200)x+(49/160000) = 609/160000
Adding 49/160000 has completed the left hand side into a perfect square :
x2+(7/200)x+(49/160000) =
(x+(7/400)) • (x+(7/400)) =
(x+(7/400))2
Things which are equal to the same thing are also equal to one another. Since
x2+(7/200)x+(49/160000) = 609/160000 and
x2+(7/200)x+(49/160000) = (x+(7/400))2
then, according to the law of transitivity,
(x+(7/400))2 = 609/160000
We'll refer to this Equation as Eq. #7.3.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x+(7/400))2 is
(x+(7/400))2/2 =
(x+(7/400))1 =
x+(7/400)
Now, applying the Square Root Principle to Eq. #7.3.1 we get:
x+(7/400) = √ 609/160000
Subtract 7/400 from both sides to obtain:
x = -7/400 + √ 609/160000
Since a square root has two values, one positive and the other negative
x2 + (7/200)x - (7/2000) = 0
has two solutions:
x = -7/400 + √ 609/160000
or
x = -7/400 - √ 609/160000
Note that √ 609/160000 can be written as
√ 609 / √ 160000 which is √ 609 / 400
Solve Quadratic Equation using the Quadratic Formula
7.4 Solving 2000x2+70x-7 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 2000
B = 70
C = -7
Accordingly, B2 - 4AC =
4900 - (-56000) =
60900
Applying the quadratic formula :
-70 ± √ 60900
x = ————————
4000
Can √ 60900 be simplified ?
Yes! The prime factorization of 60900 is
2•2•3•5•5•7•29
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 60900 = √ 2•2•3•5•5•7•29 =2•5•√ 609 =
± 10 • √ 609
√ 609 , rounded to 4 decimal digits, is 24.6779
So now we are looking at:
x = ( -70 ± 10 • 24.678 ) / 4000
Two real solutions:
x =(-70+√60900)/4000=(-7+√ 609 )/400= 0.044
or:
x =(-70-√60900)/4000=(-7-√ 609 )/400= -0.079
Two solutions were found :
- x =(-70-√60900)/4000=(-7-√ 609 )/400= -0.079
- x =(-70+√60900)/4000=(-7+√ 609 )/400= 0.044
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