Solution - Adding, subtracting and finding the least common multiple
Other Ways to Solve
Adding, subtracting and finding the least common multipleStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "a2" was replaced by "a^2".
Step 1 :
3
Simplify —
4
Equation at the end of step 1 :
1 3 1 3
(((((—•(a2))-((—•a)•b))+ac)+(—•a))-(—•b))+c
2 4 2 4
Step 2 :
1
Simplify —
2
Equation at the end of step 2 :
1 3 1 3b
(((((—•(a2))-((—•a)•b))+ac)+(—•a))-——)+c
2 4 2 4
Step 3 :
3
Simplify —
4
Equation at the end of step 3 :
1 3 a 3b (((((—•(a2))-((—•a)•b))+ac)+—)-——)+c 2 4 2 4Step 4 :
1 Simplify — 2
Equation at the end of step 4 :
1 3ab a 3b
(((((—•a2)-———)+ac)+—)-——)+c
2 4 2 4
Step 5 :
Equation at the end of step 5 :
a2 3ab a 3b
((((—— - ———) + ac) + —) - ——) + c
2 4 2 4
Step 6 :
Calculating the Least Common Multiple :
6.1 Find the Least Common Multiple
The left denominator is : 2
The right denominator is : 4
| Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
|---|---|---|---|
| 2 | 1 | 2 | 2 |
| Product of all Prime Factors | 2 | 4 | 4 |
Least Common Multiple:
4
Calculating Multipliers :
6.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 2
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
6.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. a2 • 2 —————————————————— = —————— L.C.M 4 R. Mult. • R. Num. 3ab —————————————————— = ——— L.C.M 4
Adding fractions that have a common denominator :
6.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
a2 • 2 - (3ab) 2a2 - 3ab
—————————————— = —————————
4 4
Equation at the end of step 6 :
(2a2 - 3ab) a 3b
(((——————————— + ac) + —) - ——) + c
4 2 4
Step 7 :
Rewriting the whole as an Equivalent Fraction :
7.1 Adding a whole to a fraction
Rewrite the whole as a fraction using 4 as the denominator :
ac ac • 4
ac = —— = ——————
1 4
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Step 8 :
Pulling out like terms :
8.1 Pull out like factors :
2a2 - 3ab = a • (2a - 3b)
Adding fractions that have a common denominator :
8.2 Adding up the two equivalent fractions
a • (2a-3b) + ac • 4 2a2 - 3ab + 4ac
———————————————————— = ———————————————
4 4
Equation at the end of step 8 :
(2a2 - 3ab + 4ac) a 3b
((————————————————— + —) - ——) + c
4 2 4
Step 9 :
Step 10 :
Pulling out like terms :
10.1 Pull out like factors :
2a2 - 3ab + 4ac = a • (2a - 3b + 4c)
Calculating the Least Common Multiple :
10.2 Find the Least Common Multiple
The left denominator is : 4
The right denominator is : 2
| Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
|---|---|---|---|
| 2 | 2 | 1 | 2 |
| Product of all Prime Factors | 4 | 2 | 4 |
Least Common Multiple:
4
Calculating Multipliers :
10.3 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 1
Right_M = L.C.M / R_Deno = 2
Making Equivalent Fractions :
10.4 Rewrite the two fractions into equivalent fractions
L. Mult. • L. Num. a • (2a-3b+4c) —————————————————— = —————————————— L.C.M 4 R. Mult. • R. Num. a • 2 —————————————————— = ————— L.C.M 4
Adding fractions that have a common denominator :
10.5 Adding up the two equivalent fractions
a • (2a-3b+4c) + a • 2 2a2 - 3ab + 4ac + 2a
—————————————————————— = ————————————————————
4 4
Equation at the end of step 10 :
(2a2 - 3ab + 4ac + 2a) 3b
(—————————————————————— - ——) + c
4 4
Step 11 :
Step 12 :
Pulling out like terms :
12.1 Pull out like factors :
2a2 - 3ab + 4ac + 2a =
a • (2a - 3b + 4c + 2)
Trying to factor a multi variable polynomial :
12.2 Split 2a - 3b + 4c + 2
into two 2-term polynomials
- 3b + 2a and + 4c + 2
This partition did not result in a factorization. We'll try another one:
2a - 3b and + 4c + 2
This partition did not result in a factorization. We'll try another one:
2a + 4c and - 3b + 2
This partition did not result in a factorization. We'll try another one:
2a + 2 and + 4c - 3b
This partition did not result in a factorization. We'll try another one:
+ 2 + 2a and + 4c - 3b
This partition did not result in a factorization. We'll try another one:
+ 4c + 2a and - 3b + 2
All three partitions failed. Tiger finds no factorization
Adding fractions which have a common denominator :
12.3 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
a • (2a-3b+4c+2) - (3b) 2a2 - 3ab + 4ac + 2a - 3b
——————————————————————— = —————————————————————————
4 4
Equation at the end of step 12 :
(2a2 - 3ab + 4ac + 2a - 3b)
——————————————————————————— + c
4
Step 13 :
Rewriting the whole as an Equivalent Fraction :
13.1 Adding a whole to a fraction
Rewrite the whole as a fraction using +4 as the denominator :
c c • 4
c = — = —————
1 4
Adding fractions that have a common denominator :
13.2 Adding up the two equivalent fractions
(2a2-3ab+4ac+2a-3b) + c • 4 2a2 - 3ab + 4ac + 2a - 3b + 4c
——————————————————————————— = ——————————————————————————————
4 4
Trying to factor by pulling out :
13.3 Factoring: + 2a2 - 3ab + 4ac + 2a - 3b + 4c
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -3ab - 3b
Group 2: + 4ac + 4c
Group 3: + 2a2 + 2a
Pull out from each group separately :
Group 1: ( + a + 1) • (-3b)
Group 2: ( + a + 1) • (4c)
Group 3: ( + a + 1) • (2a)
Add 1+2+3 : ————————————————
( + a + 1) • ( + 2a - 3b + 4c)
Which is the desired factorization
Final result :
(2a + 3b + 4c) • (a + 1)
————————————————————————
4
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