Solution - Adding, subtracting and finding the least common multiple
Other Ways to Solve
Adding, subtracting and finding the least common multipleStep by Step Solution
Step 1 :
Equation at the end of step 1 :
x 1 1
(—-(y-x))————————-———)
y( (2•(x2)) 2y2
Step 2 :
1
Simplify ———
2y2
Equation at the end of step 2 :
x 1 1 (—-(y-x))————————-———) y( (2•(x2)) 2y2Step 3 :
Equation at the end of step 3 :
x 1 1
(— - (y - x)) ÷ (——— - ———)
y 2x2 2y2
Step 4 :
1
Simplify ———
2x2
Equation at the end of step 4 :
x 1 1
(— - (y - x)) ÷ (——— - ———)
y 2x2 2y2
Step 5 :
Calculating the Least Common Multiple :
5.1 Find the Least Common Multiple
The left denominator is : 2x2
The right denominator is : 2y2
| Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
|---|---|---|---|
| 2 | 1 | 1 | 1 |
| Product of all Prime Factors | 2 | 2 | 2 |
| Algebraic Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
|---|---|---|---|
| x | 2 | 0 | 2 |
| y | 0 | 2 | 2 |
Least Common Multiple:
2x2y2
Calculating Multipliers :
5.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = y2
Right_M = L.C.M / R_Deno = x2
Making Equivalent Fractions :
5.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. y2 —————————————————— = ————— L.C.M 2x2y2 R. Mult. • R. Num. x2 —————————————————— = ————— L.C.M 2x2y2
Adding fractions that have a common denominator :
5.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
y2 - (x2) y2 - x2
————————— = ———————
2x2y2 2x2y2
Equation at the end of step 5 :
x (y2 - x2)
(— - (y - x)) ÷ —————————
y 2x2y2
Step 6 :
x
Simplify —
y
Equation at the end of step 6 :
x (y2 - x2)
— - (y - x)) ÷ —————————
y 2x2y2
Step 7 :
Rewriting the whole as an Equivalent Fraction :
7.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using y as the denominator :
y - x (y - x) • y
y - x = ————— = ———————————
1 y
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
7.2 Adding up the two equivalent fractions
x - ((y-x) • y) xy + x - y2
——————————————— = ———————————
y y
Equation at the end of step 7 :
(xy + x - y2) (y2 - x2)
————————————— ÷ —————————
y 2x2y2
Step 8 :
xy+x-y2 y2-x2
Divide ——————— by —————
y 2x2y2
8.1 Dividing fractions
To divide fractions, write the divison as multiplication by the reciprocal of the divisor :
xy + x - y2 y2 - x2 xy + x - y2 2x2y2 ——————————— ÷ ——————— = ——————————— • ————————— y 2x2y2 y (y2 - x2)
Trying to factor a multi variable polynomial :
8.2 Factoring xy + x - y2
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Trying to factor as a Difference of Squares :
8.3 Factoring: y2 - x2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : y2 is the square of y1
Check : x2 is the square of x1
Factorization is : (y + x) • (y - x)
Dividing exponential expressions :
8.4 y2 divided by y1 = y(2 - 1) = y1 = y
Final result :
2x2y • (xy + x - y2)
————————————————————
(x + y) • (y - x)
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